The molarity of diluted solution of ba(ch3coo)2 with initial molarity of 0.1 M and diluted to 2 L is 0.008 M
Calculating molarity of the new solution (M2) we use following formula
M1*V1=M2*V2
The molarity of ba(ch3coo)2 before dilution is 0.1 M and volume (V1) is 160 ml when converted to liter = 0.16L
while the the new molarity M2 is to be calculated and diluted to 2 L.
0.100*0.16= M2*2
M2= 0.1*0.16/2
M2= 0.016/2
M2= 0.008 M
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