Question

17.6 ml of 2-methyl-2-butanol (mm: 88.15 g/mol, d: 0.805 g/ml) is treated with an excess of 8.47 m hcl (mm: 36.46 g/mol). calculate the theoretical yield of t-pentyl chloride mm: 106.59, d: 0.865 g/ml), in ml. report answer to the correct number of sig figs, but do not include units in your answer.

Answer 1

The  theoretical yield of the solution has been obtained as  17.1 g

What is the theoretical yield?

Let us recall that each time that we hear about a chemical reaction what we are talking about is the combination of two or more reactants and a product must be formed. In this case we are to find the theoretical yield of this reaction.

We have been told that the HCl is in excess thus we have the 2-methyl-2-butanol as the limiting reactant.

Mass of the solution = density * volume

Mass of the solution = 0.805 g/ml * 17.6 ml

= 14.2 g

Number of moles = mass/molar mass

= 14.2 g/88 g/mol

= 0.16 moles

Given that the reaction is 1:1, 0.16 moles of the product is obtained.

Theoretical yield = Number of moles products * molar mass of products

= 0.16 moles * 106.59 g/mol

= 17.1 g

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