The probability that their second child will be unaffected is 3/4.
Probability is the branch of discrete mathematics. It is used for calculating how likely an event is to occur or happen. Probability is calculated by the formula:
P(E) = number of possible outcomes / total number of outcomes
The disease PKU known as Phenylketonuria is a rare inherited disorder. If the mother and father had and passed on the changed gene, then the child can inherit PKU. This is known as autosomal recessive.
The child to be affected by PKU, has to be aa. So, the first child who has the disease is aa. The unaffected child i.e. the second child is AA and Aa.
Here, the number of possible outcomes = 3 and total number of outcomes = 4
P(E) = 3 / 4
= 0.75
Therefore, the probability that the second child will be unaffected is 75%.
To know more about probability problems refer to:
https://brainly.com/question/25870256
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