produced items are shipped in groups of 25. it is known that 90% of the items do not need warranty service. calculate the mean and standard deviation

Respuesta :

90% of the items do not need warranty service so we can say that 10% of the items need warranty service of Mean is 2.5 and the standard deviation is 1.5.

So mean of the number of items that need warranty service in a batch of 25 items = 10% of 25 = 0.1×25 = 2.5

The standard deviation of the number of items that need warranty service in a batch of 25 items = sqrt(p×(1-p)/n))×batch size

= √(0.1×0.9/25)×25

= √sqrt(0.0036)×25 = 0.06×25 = 1.5

So mean = 2.5 and Standard deviation = 1.5

In data and arithmetic, the deviation is a measure that is used to find the difference between the discovered fee and the expected fee of a variable. In simple words, the deviation is the space from the middle factor. A fashionable deviation (or σ) is a measure of how dispersed the statistics are with regard to the mean. Low general deviation approach records are clustered around the suggest, and high trendy deviation suggests facts are greater unfold out.

suggest deviation is a statistical degree that computes the average deviation from the common fee of a given facts series. The implied deviation may be calculated by the usage of various information series, inclusive of – non-stop information collection, discrete records collection, and individual information series. A deviation is any unwanted event that differs from the authorized techniques, methods, instructions, specifications, or mounted standards.

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