Question

two planes start from los angeles international airport and fly in opposite directions. the second plane starts 1 2 hour after the first plane, but its speed is 80 kilometers per hour faster. find the speed of each plane when 2 hours after the first plane departs the planes are 3025 kilometers apart.

Answer 1

The speed of each plane is 830.

The Distance can be said as the space between two things. Distance is calculated by multiplying speed by time. Speed can be said as the rate at which an object moves. Speed is calculated using distance by time. Time can be said as a period of action. Time can be calculated using distance by speed.

As per the given problem,

speed of the first plane = x

speed of the second plane = x + 80

time of the first plane = 2 hours

time of the second plane = 1.5 hours

We know that,      Distance = Speed * Time

⇒ 2x + 1.5(x + 80) = 3025

⇒ 2x + 1.5x + 120 = 3025

⇒ 3.5x = 3025 - 120

⇒ 3.5x = 2905

⇒ x = 2905 / 3.5

⇒ x = 830

Therefore, the speed of each plane is 830 km when the planes are 3025 km apart.

To know more about speed problems refer to:

https://brainly.com/question/14963148

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