Question

the concentration of h3aso3 in a solution is determined by titration with a 0.1977 m ce4 solution. the balanced net ionic equation for the reaction is:

Answer 1

0.071M is he concentration of the H3AsO3 solution when 24.14 mL of the 0.1177 M Ce4+ solution is required to react completely with 40.00 mL of the H3AsO3 solution .

What is Ce4+?

Ce4+  is monoatomic tetra cation where  Ce stands for Cerium.

What is H3AsO3?

H3AsO3 stands for Arsenous acid and is an inorganic compound usually known to occur as aqueous form.

As per the given data:

C1=0.1177M

V1=24.14 ml=0.02414l

C2=?

V2=40.00ml=0.040L

So now to find the C2

we do as follows

C1V1=C2V2

rearranging for C2

C2=C1*V1/V2

Putting the values provided

C2=0.1177*0.02414/0.040

C2=0.071M

Hence, 0.071M is he concentration of the H3AsO3 solution when 24.14 mL of the 0.1177 M Ce4+ solution is required to react completely with 40.00 mL of the H3AsO3 solution .

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I understand your question which is :

the concentration of h3aso3 in a solution is determined by titration with a 0.1977 m ce4 solution. the balanced net ionic equation for the reaction is: 2Ce4+(aq) + H3AsO3(aq) + 5H2O(l) 2Ce3+(aq) + H3AsO4(aq) + 2H3O+(aq) In one experiment, 24.14 mL of the 0.1177 M Ce4+ solution is required to react completely with 40.00 mL of the H3AsO3 solution. Calculate the concentration of the H3AsO3 solution.