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Suppose that you are holding a pencil balanced on its point. If you release the pencil and it begins to fall, what will be the angular acceleration when it has an angle of 10. 0 degrees from the vertical? a typical pencil has an average length of 15. 0 cm and an average mass of 10. 0 g. Assume the tip of the pencil does not slip as it falls.

Respuesta :

Answer: 0.4299s.

Explanation: To find the angular acceleration ,Newton's second angular law will be used.

τ = I α

Wr = I α

The weight is applied in the middle of the pencil , sin 10 = r / (L/2).

r = L/2 sin 10

the moment of inertia will be: I = 1/3 M L²

mg L / 2 sin 10 = (1/3 m L²) α  

αf = 3/2 g / L sin 10

α  = [3/2 × 9.8] / [0.150 sin10]

α  = 17 rad/s²

angle from the vertical to the ground θ = π / 2

t = √ (2 π / (2 α ))

t = √(π / α )

t = √(π / 17)

t = √3.142 / 17

t = 0.4299s

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