Using Normal distribution and sample proportion, the smallest possible value of n is 25 for which the distribution is normal .
Sample proportion:
Sample proportions are obtained in the following situations:
we have given that
The value of probability (p) = 3/5 = 0.6 It is necessary that for the value of n probability of normal distribution satisfied the required condition,
if both of above conditions are satisfied then the distribution is Normal .
we have to find smallest value of n such that the distribution become normal .
Now, n× 0.6 ≥ 10
=> n ≥ 16.6
and n (1 - p) ≥ 10
=> n(1 - 0.6) ≥ 10
=> n × 0.4 ≥ 10
=> n ≥ 25
Hence, the smallest value of n is 25
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Complete question:
If p = 3/5, what is the smallest value of n that satisfies the requirements for a normally distributed p?