Respuesta :

Using quadratic equations,

the roots of provided quadratic equation, x^2-12x+59= 0 has two imaginary roots i.e.,

x = 6+4i , 6-4i.

Quadratic equations:

A quadratic equation in mathematics is a quadratic equation of the form ax² + bx + c = 0.

where a, b , c are the constant term, and a not equal to zero and x is the variable.

Variable x is quadratic, so this quadratic equation has two roots or answers.

For the quadratic equation ax² + bx + c = 0, the root is computed by the formula,

x = (-b ± √ (b² - 4ac) )/2a

  • If D = 0, the equation has roots are real and distinct numbers.
  • If D >0 , the equation has roots equal to two real and equal numbers.
  • If D< 0 , the equation has imaginary roots.

we have given that,

x² - 12x + 59 = 0

Which is Quadratic equation. We want to find out the roots of equation. So, here we use quadratic formula for finding roots of the equation

x = {-b ± √b² - 4ac}/2a

Here a = 1; b = -12; c = 59

x = {-(-12) ± √(-12)² - 4(59)}/2(1)

x = {12 ± √144 - 236}/2

x = {12 ± √-92}/2

x = 12 ± 9.6i /2

x = 6 ± 4.8i

Hence, given equation has imaginary roots .

To learn more about quadratic equations, refer:

https://brainly.com/question/1214333

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