a fruit fly of genotype br/br is testcrossed with a fruit fly of genotype br/br. in 84% of the meioses, there are no chiasmata between the linked genes, but in 16% of the meioses there is one chiasmata between the genes. what proportion of the progeny willbe br/br?

Respuesta :

The proportion of the progeny will be Br/br is 4%,

A chiasm is a form of the crossing of two chromatids of a chromosome with its homologous chromosome pair. Crossing over is the exchange of non-sister chromatid segments of a pair of homologous chromosomes. Crossing over occurs during the meiotic division I, namely at the end of prophase I or the beginning of metaphase I.

B and R are linked genes in fruit flies. Fruit fly genotype BR/br crossed with br/br. In 84% of meiosis there are no chiasmas between linked genes; In 16% of meiosis there is a single chiasm between genes.

Parental: BRbr    >< brbr

Genom: BR, br, bR, Br   >< br

Filial:

BR/br_____ ¼

br/br______¼

bR/br_____ ¼

Br/br______¼

The proportion of the progeny will be Br/br:

Br/br  ¼ ⇒ ¼ x 16% = 40%

Learn more about crossing over at https://brainly.com/question/927405

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