samia set off on her bicycle to visit her friend, traveling at an average speed of 17 kilometers per hour. when she had gone half the distance to her friend's house, a tire went flat, and she walked the rest of the way at 5 kilometers per hour. in all, it took her 44 minutes to reach her friend's house. in kilometers rounded to the nearest tenth, how far did samia walk?

Let's consider the distance that Samia had to travel in total is 2x. We know that the length of the bike ride and how far she walked are equal, so they are both (2x/2) or x.

She bikes at an average speed of 17 kph, so she travels the distance she bikes in (x/17) hours. She walks at a rate of 5 kph, so she travels the distance she walks in (x/5) hours. Now we use an algebraic expression as follows;

The total time is;

(x/17) + (x/5) = 22x/85.

This is equal to (44/60) = (11/15) of an hour.

Now solving for x;

22x ÷ 85 = 11 ÷ 15

22x = 85 × (11 ÷ 15)

22x = 62.33

x = 62.33 ÷ 22

x = 2.8

Since x is the distance of how far Samia traveled by both walking and biking, and we need to know how far Samia walked to the nearest tenth, we have the result that Samia walked about 2.8 Km.

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