Question

What is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5)?
Oy=3/5x-20
Oy=-3/5x+20
O y=5/3x-20
y=-5/3x+20

Answer 1

Answer:

  (d)  y = -5/3x+20

Step-by-step explanation:

You want the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5).

Slope

The slopes of perpendicular lines are opposite reciprocals of one another. The slope (m') of the perpendicular line is ...

  m' = -1/m . . . . .  where m is the slope of the given line

Application

The given line's equation is in slope-intercept form. The slope of it is the coefficient of x: 3/5. Then the slope of the perpendicular line is ...

  m' = -1/(3/5) = -5/3

Only one answer choice is an equation of a line with a slope of -5/3.

  y = -5/3x +20