If 90% of a chemical is removed by first-order reaction in 24 h, are the half-life (in h) and rate constant (1/h) of the reaction is 3x 10 ^13.
For the primary order response, time required for 99% final touch. Hence, time required for 99% final touch is two times for the time required for the final touch of 90% response. the price = k[A] [B]2 with k = 2.zero x 10–6 mol/2L2s/1.3t1/2.
For the primary order response, time required for 99% final touch. Hence, time required for 99% final touch is two times for the time required for the final touch of 90% response. the price = k[A] [B]2 with k = 2.zero x 10–6 mol–2L2s–1.3t1/2.
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