Question

the balmer series of lines emitted by doubly ionized lithium (li ), which has atomic number 3, consists of electron transitions that end at the first excited state. find the limiting wavelength of the balmer series of doubly ionized lithium. (b) find the longest wavelength at which doubly ionized lithium in its ground state can absorb a photon

Answer 1

Among electromagnetic waves, UV rays are most dangerous because exposure to these radiation cause serious problems in living organism. Therefore, the longest  wavelength in Balmer series is 656nm.

What is electromagnetic wave?

Electromagnetic wave is a wave which contain two component one is electric component and other is magnetic component. The electric and magnetic component are perpendicular to each other. There are so many wave that comes under electromagnetic wave like infrared wave , radio wave.

There is a relation between energy of wave,  frequency of wave, and wavelength of wave.

Mathematically,

E=hc/λ

For Balmer series,

n1​ = 2

For longest wavelength in Balmer series, minimum energy transition is to be considered because wavelength is inversely proportional to Energy.

n2​ = 3

λ1​=1.097×10⁻²nm−1×12(221​−321​)

⇒λ=656nm

Therefore, the longest  wavelength in Balmer series is 656nm.

To know more about electromagnetic wave, here:

https://brainly.com/question/12289372

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