Question

What volume will 1431. 5 g of sulfur hexafluoride (sf6) gas occupy if the temperature and pressure of the gas are 105oc and 9. 4 atm, respectively? report answer to 1 decimal point.

Answer 1

The Volume of SF₆ gas  at given temperature and pressure will be 39.9 L .This can be determined by the Ideal Gas Law to solve this problem.

According to ideal gas equation,

pV = nRT

Since moles =mass /molar mass

 or n= m/M

Or  we can write,

PV= m/M × RT

We can rearrange this to

PM= m/V × RT

But density =  mass/ volume

 or ρ= m/V

∴ PM=ρRT and

ρ= PM/ RT

It is given that,

P= 9.4 atm ≈ 9.4 bar

and T= 105°C

and the molar mass of SF₆  is 146.06 g/mol

ρ=  9.4 × 146.06 / 0.08314 × 403

=  1372/ 33.5

= 40.9 g/L

Now, calculating the volume from the value of density,

ρ= m/V

V =m/ρ

V= 1431.5 /40.955

V= 34.9 L

So, the volume will be 34.9 L

To know more about calculating volume occupied by gas, please refer:

https://brainly.com/question/10128131

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