A line passes through (–7, –5) and (–5, 4).Write an equation for the line in point-slope form.
Rewrite the equation in standard form using integers.

Respuesta :

The equation for point slope would equal 2.
[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -7}}\quad ,&{{ -5}})\quad % (c,d) &({{ -5}}\quad ,&{{ 4}}) \end{array} \\\quad \\\\ % slope = m slope = {{ \boxed{m}}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}} \\ \quad \\\\ % point-slope intercept y-{{ y_1}}={{\boxed{ m}}}(x-{{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}[/tex]

now, the standard form, simply means, move everything to the left-hand-side, and make it = 0, so, only 0 on the right-hand-side

now. integers only, well, let's see what you get first, then you can get rid of any rationals
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