Respuesta :
[tex]\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -7}}\quad ,&{{ -5}})\quad
% (c,d)
&({{ -5}}\quad ,&{{ 4}})
\end{array}
\\\quad \\\\
% slope = m
slope = {{ \boxed{m}}}= \cfrac{rise}{run} \implies
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}
\\ \quad \\\\
% point-slope intercept
y-{{ y_1}}={{\boxed{ m}}}(x-{{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}[/tex]
now, the standard form, simply means, move everything to the left-hand-side, and make it = 0, so, only 0 on the right-hand-side
now. integers only, well, let's see what you get first, then you can get rid of any rationals
now, the standard form, simply means, move everything to the left-hand-side, and make it = 0, so, only 0 on the right-hand-side
now. integers only, well, let's see what you get first, then you can get rid of any rationals