Respuesta :

A = P(1+r/n)^nt 

A = 4000(1+.06)^5 

n = 1 since it is compounded annually.

Answer:

The balance in the account after the given period is [tex]\$5,352.90[/tex]  

Step-by-step explanation:

we know that

The compound interest formula is equal to  

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

[tex]t=5\ years\\ P=\$4,000\\ r=0.06\\n=1[/tex]  

substitute in the formula above  

[tex]A=\$4,000(1+\frac{0.06}{1})^{1*5}=\$5,352.90[/tex]  

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