Respuesta :
A = P(1+r/n)^nt
A = 4000(1+.06)^5
n = 1 since it is compounded annually.
A = 4000(1+.06)^5
n = 1 since it is compounded annually.
Answer:
The balance in the account after the given period is [tex]\$5,352.90[/tex]
Step-by-step explanation:
we know that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
[tex]t=5\ years\\ P=\$4,000\\ r=0.06\\n=1[/tex]
substitute in the formula above
[tex]A=\$4,000(1+\frac{0.06}{1})^{1*5}=\$5,352.90[/tex]