In the paper airplane,ABC≠EFGH m<B = m<BCD = 90°, and m<BAD = 131°. Find m<GHE.
a.
131°
b.
49°
c.
90°
d.
59°
![In the paper airplaneABCEFGH mltB mltBCD 90 and mltBAD 131 Find mltGHE a 131 b 49 c 90 d 59 class=](https://us-static.z-dn.net/files/d66/58e62b75147626a4094fe5ceb48bca88.png)
The measure of m<GHE is 49°, the correct option is B.
A quadrilateral is a polygon with four sides.
It is of various types,
Trapezoid, which have one pair of parallel sides,
Parallelogram, it has two pairs of parallel sides,
Rhombus, it has all sides equal,
Rectangle, opposite sides are parallel and equal, and,
Square, all sides are equal and opposite sides are parallel, and all angles have measure of 90 degree.
The quadrilateral ABCD is ≅ quadrilateral EFGH
When two figures are congruent then by CPCTC, corresponding parts of congruent figures are congruent.
The measure of the angle
B = m<BCD = 90°
m<BAD = 131°
As the quadrilaterals are congruent,
By CPCTC
∠F = ∠FGH = 90°
m ∠FEH = 131°
The measure of m<GHE has to be determined.
The sum of the measures of all angle so of a quadrilateral is 360 degree.
The ∠F + ∠FGH + ∠FEH + ∠GHE = 360
90 +90+ 131 +∠GHE = 360
∠GHE = 49°
To know more about Quadrilateral
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