Respuesta :
Data on the missing table.
time (seconds) x ; 0 1 2 3 4 5
height (meters) y ; 0 40 60 60 40 0
We simply substitute the values of x and y to see if they are equal.
x = 2 ; y = 60
y = -10(x) (x-5)
60 = -10(2) (2-5)
60 = -20 (-3)
60 = 60 CORRECT
y = 10(x) (x-5)
60 = 10(2) (2-5)
60 = 20 (-3)
60 = -60 INCORRECT
y = -10(x-5)
60 = -10(2-5)
60 = -10(-3)
60 = 30 INCORRECT
y = 10(x-5)
60 = 10(2-5)
60 = 10(-3)
60 = -30 INCORRECT
The equation that models the height,y, x seconds after firing is y = -10(x) (x-5)
time (seconds) x ; 0 1 2 3 4 5
height (meters) y ; 0 40 60 60 40 0
We simply substitute the values of x and y to see if they are equal.
x = 2 ; y = 60
y = -10(x) (x-5)
60 = -10(2) (2-5)
60 = -20 (-3)
60 = 60 CORRECT
y = 10(x) (x-5)
60 = 10(2) (2-5)
60 = 20 (-3)
60 = -60 INCORRECT
y = -10(x-5)
60 = -10(2-5)
60 = -10(-3)
60 = 30 INCORRECT
y = 10(x-5)
60 = 10(2-5)
60 = 10(-3)
60 = -30 INCORRECT
The equation that models the height,y, x seconds after firing is y = -10(x) (x-5)
The table shows the approximate height of a projectile x (seconds) after being fired into the air, the equation models the height y & x seconds after firing is [tex]\rm y = -10(x)(x - 5)[/tex]
To check which of the following equations are true for the given statement we need to simplify conditions.
Given:
- x = represents seconds taken after being fired into the air.
- y= represents height of a projectile.
TABLE :-
x= Time (in seconds) : 0 1 2 3 4 5
y= Height (in meters) : 0 40 60 60 40 0
We will now solve the given equations by substituting the values of x & y to check if they are equal i.e. if LHS= RHS
Lets take values from given table,
Time x = 2 & Height y = 60 in option (1) [tex]\rm y = -10(x)(x - 5)[/tex]
[tex]\rm y = -10(x) (x-5)\\60 = -10(2) (2-5)\\60 = -20 (-3)\\60 = 60[/tex]
On solving, we get LHS=RHS , Therefore given equation (1) [tex]\rm y = -10(x)(x - 5)[/tex] is CORRECT
Therefore , [tex]\rm y = -10(x)(x - 5)[/tex] is the Correct equation that models the height-y & x-secongd after firing.
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