Respuesta :
The volume of the cone :V = 1/3 r² π hr = 9 cm, h = 6 cm and π = 3.14V = 1/3 · 9² · 3.14 · 6V = 81 · 3.14 · 2V = 508.86 ≈ 509Answer:C ) 509 cm³
The required approximate value volume of the cone is v = 509`cm³.
Given that ,
Height of the cone = 6m
Radius of the cone = 9m
We have to find,
The approximate volume of the cone .
According to the question,
The volume of a cone is equal to one-third of the volume of a cylinder having the same base radius and height.
Where V is the volume, r is the radius and h is the height.
The volume of the cone
[tex]v = \frac{1}{3} \pi r^{2} h[/tex]
Where, r = 9 cm, h = 6 cm and π = 3.14
V = [tex]\frac{1}{3} (3.14) (9)^{2} (6)[/tex]
V = 508.86 ≈ 509`cm³
Hence, The required approximate value volume of the cone is v = 509`cm³
For the more information about Volume of the cone click the link given below.
https://brainly.com/question/15171467