Question

which point is an x-intercept of the quadratic function
f(x)=(x=+6)(x-3)

Answer 1

     The x-intercept of a quadratic function is the x-value of the function (if there is any) that has a y-coordinate of zero. Hence, you can solve for the roots of this function and if you're using a graphing calculator, you may graph this function to find the roots that intercepts the x-axis. You could also just substitute 0 for f(x), since f(x)=y and that'd be the equivalent of having a y-coordinate of zero to find the x-intercept.

Answer 2

Answer:

$(-6,0)$

$(3,0)$

Step-by-step explanation:

We have been given an quadratic function $f(x)=(x+6)(x-3)$.

To find the x-intercept of he given function, we will equate our given function equal to zero.

Using zero product property we will get,

$(x+6)(x-3)=0$

$(x+6)=0\text{ or }(x-3)=0$

$x+6=0\text{ (or) }x-3=0$

$x+6-6=0-6\text{ (or) }x-3+3=0+3$

$x=-6\text{ (or) }x=3$

Since y-coordinate is zero at x-axis, therefore, the x-intercepts of our given function would be $(-6,0)$ and $(3,0)$.