Molecular mass of Carbon in compound = 29.784% * 241.94 g/mol
= 72.05 g/mol
Number of moles = 72.05 / 12 = 6 [ Molar mass of Carbon = 12 ]
Now, Molecular mass of Hydrogen in compound = 4.166% * 241.94 g/mol
= 10.07 g/mol
Number of moles = 10.07 / 1 = 10 [ Molar mass of Hydrogen = 1 ]
Now, Molecular mass of Bromine in compound = 66.05% * 241.94 g/mol
= 159.80
Number of moles = 159.80 / 79.90 = 2
Empirical Formula = C₆H₁₀Br₂
Hope this helps!
