Respuesta :

use quadratic formula

for ax^2+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]

given
2x^2+23x-19=0
a=2
b=23
c=-19

x=[tex] \frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)} [/tex]
x=[tex] \frac{-23+/- \sqrt{529-152} }{4} [/tex]
x=[tex] \frac{-23+/- \sqrt{377} }{4} [/tex]

x=[tex] \frac{-23+ \sqrt{377} }{4} [/tex] or [tex] \frac{-23- \sqrt{377} }{4} [/tex]
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