If the theoretical yield of the reaction below corresponds to 99.2 g and the actual yield was 60.9 g, calculate the percent yield.Given: Li2O + H2O —> 2 LiOHI picked C but I’m not sure if I’m correct

If the theoretical yield of the reaction below corresponds to 992 g and the actual yield was 609 g calculate the percent yieldGiven Li2O H2O gt 2 LiOHI picked C class=

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Explanation:

To solve this question, we need to use the following formula:

percent yield = (actual yield/theoretical yield)*100%

The question gives us:

actual yield = 60.9 g

theoretical yield = 99.2 g

percent yield = (60.9/99.2)*100%

percent yield = 61.4%

Answer: 61.4%

alternative "A"

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