Lateral area of a square pyramid: This area is equal to 4 times the area of one of the triangles (as each triangle that comform the laterals of a pyramid with a square base are equa)
[tex]\begin{gathered} LA=4(\frac{1}{2}b_{\Delta}\cdot h_{\Delta}) \\ \\ LA=2b_{\Delta}h_{\Delta} \end{gathered}[/tex]
For the given pyramid:
base of the lateral triangles: 14 cm
heigh of the lateal triangles: 14/2 cm = 7cm
[tex]\begin{gathered} LA=2(14\operatorname{cm})(7\operatorname{cm}) \\ LA=196cm^2 \end{gathered}[/tex]Then, the lateral area is 196 square centimeters
