Question

The gas/oil ratio for a certain chainsaw is 50 to 1.a. How much oil (in gallons) should be mixed with 13 gallons of gasoline? b. If 1 gallon equals 128 fluid ounces, write the answer to part a in fluid ounces.

Answer 1

$\begin{gathered} a)\frac{13}{50} \\ b)33.28fl.oz \end{gathered}$

1) We can write the following ratio for this, considering the ratios and the quantities:

a)

$\begin{gathered} \frac{50}{1}=\frac{13}{x} \\ 50x=13 \\ x=\frac{13}{50}\text{ (or 0.26g)} \end{gathered}$

Notice that on the left side, the ratio gas/oil, and on the right side is the quantity of gas and the unknown quantity of oil.

So, so far we have 13/50 gallons of oil that must be mixed with gasoline.

b) For now, we need to convert that from gallons to fluid ounces so we can write out the following product:

$\begin{gathered} x=\frac{13}{50}\times128 \\ x=33.28fl\text{ oz} \end{gathered}$

So 13/50 or 0.26 gallons of oil. b) 33.28 fl oz.