Question

The y-value of which function’s y-intercept is larger, f or h?

Answer 1

Answer:

h

Explanation:

The y-value of the y-intercept is the value of y when x is equal to 0, so for the first function, we need to calculate f(x) for x = 0 as:

$\begin{gathered} f(x)=\log _2(x+8) \\ f(0)=\log _2(0+8) \\ f(0)=\log _2(8) \\ f(0)=3 \end{gathered}$

So, the y-value of the first function's y-intercept is 3.

On the other hand, for the second function, when x = 0, h(x) is 4. It means that the y-value of the second function's y-intercept is 4.

Since 4 is larger than 3, the function with the largest y-value in its y-intercept is h(x). So, the answer is h(x)