Solution
[tex]x^3+3x^2-6x-18[/tex]We can do the following:
[tex]x^2(x+3)-6(x+3)=(x+3)(x^2-6)[/tex]Then the correct answer would be:
[tex]B\mathrm{}(x^2-6)(x+3)[/tex]For the second case we have the following:
[tex]9x^2-64y^2[/tex]We can do this:
[tex](3x-8y)(3x+8y)[/tex]