Respuesta :

Solution

We have the following equation:

5(x+3)= 3y+12 (1)

Solving for y we got:

3y= -12+ 5(x+3)

3y = -12 + 5x+15

3y= 5x +3

y= 5/3 x +1

The slope for the first case is: m1= 5/3

5x + 3y = 15 (2)

Solving for y we got:

3y= 15-5x

y= 5 -5/3x

The slope is given by : m2= -5/3

Then m1*m2 is not equal to -1 (NOT perpendicular)

m1 is different from m2 (NOT parallel)

Then are not perpendicular or parallel

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