Question

tsThe table below represents the concessions sold at the last three basketball games. Thegames were held on different days and times.Friday nightSaturday morningTuesday nightTotalCandy1489478320Hot Dogs10227150279Nachos Total1084297247358163325846What is the approximately probability of a person buying a hot dog and going to a Tuesdaynight game?

Answer 1

Given:

The total = 846.

The number of hot dogs sold at Tuesday night = 150.

Required:

We need to find the approximate probability of a person buying a hot dog and going to a Tuesday night game.

Explanation:

The total possible outcomes = 846.

$n(S)=846$

Let A be the given event.

The favourable outcomes = The number of hot dogs sold at Tuesday night = 150.

$n(A)=150$

The approximate probability of a person buying a hot dog and going to a Tuesday night game.

$P=\frac{n(A)}{n(S)}\times100$$P=\frac{150}{846}\times100$$P=17.7$$P=18\text{ \%}$

Final answer:

$P=18\text{ \%}$