Question

Can you help me with problem #1 I think I remember how to do it but just want to make sure

Answer 1

1)

$3x-2y=-16$

To convert this equation into slope-intercept form we have to isolate y. Subtracting 3x at both sides of the equation:

$\begin{gathered} 3x-2y-3x=-16-3x \\ -2y=-3x-16 \end{gathered}$

Dividing by -2 at both sides of the equation:

$\begin{gathered} \frac{-2y}{-2}=\frac{-3x-16}{-2} \\ y=\frac{-3x}{-2}+\frac{-16}{-2} \\ y=\frac{3}{2}x+8 \end{gathered}$