Question

?What is the factored form of x6 - 9?O(x + 3)(x – 3)(x5 + 3)(x – 3)o(x3 + 3)(x2 - 3)o(x3 + 3)(x3 - 3)+DONE

Answer 1

Answer:

$\lparen x^3+3)\left(x^3-3\right)$

Explanation:

Given the expression

$x^6-9$

It can be rewritten as

$x^{2\cdot3}-3^2=\lparen x^3)^2-3^2$

Use the formula

$a^2-b^2=\left(a+b\right)\left(a-b\right)$

to get

$\lparen x^3+3)\left(x^3-3\right)$

which is the factored form of the given expression.