Question

4.A gas occupies 8.7L at a temperature of 29.0°c. What is thevolume at 133°C? (Charles Law)

Answer 1

Answer:

11.7L

Explanations

According to Charles law, the volume of a given mass of gas is directly proportional to its temperature provided that the pressure is constant. Mathematically;

$\begin{gathered} v\alpha T \\ v=kT \\ k=\frac{v_1}{T_1}=\frac{v_2}{T_2} \end{gathered}$

where:

• v1 and v2 are the ,initial and final ,volume

,

• T1 and T2 are the, initial and final, temperature

Given the following parameters

v1 = 8.7L

T1 = 29.0°C = 29 + 273

T1 = 302K

T2 = 133+ 273 = 406K

Substitute the given parameters into the formula

$\begin{gathered} v_2=\frac{v_1T_2}{T_1} \\ v_2=\frac{8.7L\times406}{302} \\ v_2=\frac{3532.2}{302} \\ v_2=11.7L \end{gathered}$

Hence the volume of the gas at 133°C is 11.7L