Question

Which equation represents a circle centered at (3.5) and passing through the point (-2.91?OA (+3)2 + (y + 5)² = 17OB. (-3)²+(y-5)² = 17OC. (x+3)²+(y+ 5)² = 41OD. (-3)2 + (y-5)² = 41ResetNext

Answer 1

ANSWER

$(x-3)^2+(y-5)^2=41$

EXPLANATION

Given;

$\begin{gathered} center=(3,5) \\ points=(-2,9) \end{gathered}$$\begin{gathered} (x-a)^2+(y-b)^2=(r)^2 \\ (x-3)^2+(y-5)^2=(\sqrt{41})^2 \\ \end{gathered}$