Question

A hair dryer draws 6.0 A when plugged into a 120-V line. (a) What is its resistance? (b) How much charge passes through it in 15 min?

Answer 1

We will have the following:

a)

$R=\frac{120V}{6A}\Rightarrow R=20\Omega$

b)

$Q=(6A)(15min\ast\frac{60s}{1min})\Rightarrow Q=5400W$

So, the charge is 5400 W in 15 minutes.