Question

For the function f(x) = x^2 + 4, identify the values of f(0), f(1/2), and f(-1).

Answer 1

Explanation:

The function is given below as

$f(x)=x^2+4$

Find

$\begin{gathered} f(0) \\ put\text{ }x=0 \\ f(0)=(0)^2+4 \\ f(0)=4 \end{gathered}$$\begin{gathered} f(\frac{1}{2}) \\ put\text{ }x=\frac{1}{2} \\ f(\frac{1}{2})=(\frac{1}{2})^2+4 \\ f(\frac{1}{2})=\frac{1}{4}+4 \\ f(\frac{1}{2})=\frac{17}{4} \end{gathered}$$\begin{gathered} f(-1) \\ put\text{ }x=-1 \\ f(-1)=(-1)^2+4 \\ f(-1)=1+4 \\ f(-1)=5 \end{gathered}$

Hence,

The final answer is

$4,\frac{17}{4},5$

The FIRST OPTION is the correct answer