Respuesta :

Given

Amount of water,

[tex]m=20\text{ ml}[/tex]

Temperature is,

[tex]T=0.00C[/tex]

To find:

Energy required to freeze the water.

Explanation:

The latent heat of fusion is

[tex]L=33.5\times10^4\text{ J/}kg[/tex]

Converting the amount of water to kg,

[tex]m=0.020kg[/tex]

Thus the energy required is:

[tex]\begin{gathered} H=mL \\ \Rightarrow H=0.020\times33.5\times10^4=0.67\times10^4J \end{gathered}[/tex]

Conclusion:

The amount of energy required is

[tex]0.67\times10^4J[/tex]

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