How much energy is required to freeze 20 ml of water already at 0.0 0C?
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Given
Amount of water,
[tex]m=20\text{ ml}[/tex]Temperature is,
[tex]T=0.00C[/tex]To find:
Energy required to freeze the water.
Explanation:
The latent heat of fusion is
[tex]L=33.5\times10^4\text{ J/}kg[/tex]Converting the amount of water to kg,
[tex]m=0.020kg[/tex]Thus the energy required is:
[tex]\begin{gathered} H=mL \\ \Rightarrow H=0.020\times33.5\times10^4=0.67\times10^4J \end{gathered}[/tex]Conclusion:
The amount of energy required is
[tex]0.67\times10^4J[/tex]