Question

please answer quickly I'm just trying to confirm my answer

Answer 1

Given the following vector:

$v=<-\sqrt{3},2\sqrt{3}>$

The magnitude of the vector will be as follows:

$||v||=\sqrt{(-\sqrt{3})^2+(2\sqrt{3})^2}=\sqrt{3+12}=\sqrt{15}$

So, the answer will be option 2) ||v|| = √15