I) p = 3.5t + 5
II) p = 7t/2 - 5
A) For equation I, if we replace t with 0 we find p = 5 and if we replace t with 2 we find p = 3.5*2 + 5 = 12. Therefore, to graph the line represented by this equation, we just need to draw a line passing through the points (0,5) and (2,12)
For equation II, if we replace t with 0 we find p = -5 and if we replace t with 2 we find p = (7/2)*2 - 5 = 2. Therefore, to graph the line represented by this equation, we just need to draw a line passing through the points (0,-5) and (2,2).
Here is the system represented by a graph:
B) By the graph, we can see that the lines are parallel and never intercept each other. This happens because they have the same slope (3.5 = 7/2). Therefore, this system has no solution.
