Question

DCF = FB and AE = EBCB = 38 and AB = 22DE = [?]EBFLLEnter

Answer 1

Given

Also, CF = FB and AE = EB, CB = 38 and AB = 22.

To find the length of DE.

Explanation:

It is given that,

Also, CF = FB and AE = EB, CB = 38 and AB = 22.

That implies,

By using midpoint theorem of triangle, we have,

$DE=\frac{1}{2}BC$

Therefore,

$\begin{gathered} DE=\frac{1}{2}\times38 \\ =19 \end{gathered}$