Question

need help asappppppp

Answer 1

At first, we will find the volume of the cone and the volume of the sphere, then subtract them to find the answer

The rule of the volume of the cone is

$V_c=\frac{1}{3}\times\pi\times r^2\times h$

Since the height of the cone is 1 cm and its radius is 3 cm, then

h = 1 and r = 3

Substitute them in the rule above

$\begin{gathered} V_c=\frac{1}{3}\times\pi\times(3)^2\times(1) \\ V_c=\frac{1}{3}\times\pi\times9\times1 \\ V_c=3\pi \end{gathered}$

The formula of the volume of the sphere is

$V_{sp}=\frac{4}{3}\times\pi\times r^3$

Since the diameter of the sphere is 3 cm, then

$\begin{gathered} r=\frac{1}{2}\times3 \\ r=\frac{3}{2} \\ r=1.5\operatorname{cm} \end{gathered}$

Substitute it in the formula above

$\begin{gathered} V_{sp}=\frac{4}{3}\times\pi\times(1.5)^3 \\ V_{sp}=4.5\pi \end{gathered}$

Noe subtract them to find the answer

$\begin{gathered} V=4.5\pi-3\pi \\ V=1.5\pi \end{gathered}$

The amount of the extra soap is

$1.5\pi cm^3$