Given the expression:
[tex]10-3x^2=4[/tex]
We can find its solution by solving like a linear equation up until the exponent:
[tex]\begin{gathered} 10-3x^2=4 \\ \Rightarrow-3x^2=4-10 \\ \Rightarrow-3x^2=-6 \\ \Rightarrow x^2=\frac{-6}{-3}=2 \\ x^2=2 \end{gathered}[/tex]
now, we can apply the square root on both sides to get the following:
[tex]\begin{gathered} \sqrt[]{x^2}=\sqrt[]{2} \\ \Rightarrow x=\pm\sqrt[]{2=} \\ x=\pm1.41 \end{gathered}[/tex]
therefore, the solutions of the equation are x=1.41 and x=-1.41
