Question

6 At a 33-foot depth underwater, the pressure is 29.55 pounds per square inch (psi). At a depth of 66 feet, the pressure reaches 44.4 psi. At what rate is the pressure increasing? ur answer on ouatlon for the

Answer 1

To solve the exercise you can apply the following formula:

$rate=\frac{\text{difference in pressure}}{\text{difference in depth}}$

In this case, based on the information given in the exercise, you can identify that:

$\begin{gathered} \text{difference in pressure= (44.4.}-29.55)psi=14.85\text{ psi} \\ \text{difference in dept}=(66-33)ft=33\text{ ft} \end{gathered}$

Substituting values, you get:

$rate=\frac{14.85\text{ ps i}}{33\text{ ft}}=0.45\text{ }\frac{ps\text{ i}}{ft}$

Therefore, The pressure is increasing at 0.45 psi per foot.