time can only take values greater than or equal to zero, so the domain starts on 0
the las point of the domain is when the projectile hit the ground, this means when g=0
now we will replace g=0 o find the last value of the domain
[tex]\begin{gathered} g=0 \\ -16x^2+128x=0 \end{gathered}[/tex]solve x to know the last time
[tex]\begin{gathered} 16x(-x+8)=0 \\ -x+8=\frac{0}{16x} \\ -x+8=0 \\ -x=-8 \\ x=8 \\ \end{gathered}[/tex]the last time in seconds of the model is 8
so the domain is
[tex]\lbrack0,8\rbrack[/tex]