Question

calculate the surface area of a tetrahedron with four faces and a base of 1 square foot and a height of 0.866 foot

Answer 1

The surface area is given by:

$SA=B+\frac{1}{2}ph$

Where:

B = Area of the base

h = height

p = Perimeter of the base

so:

$\begin{gathered} SA=1+\frac{1}{2}(4)(0.866) \\ SA=2.732ft^2 \end{gathered}$