The figure shows two parallel lines AB and De cut by the transversals AE and BD ( in the picture ) Which statement best explains the relationship between ABC and EDC? A) ABC - EDC because m<3 = m<6 and m<1 = m<4B) ABC - EDC because m<3 = m<4 and m<1 = m<5 C) ABC = EDC because m<3 = m<4 and m<1 = m<5D) ABC = EDC because m<3 = m<6 and m<61 = m<4

The figure shows two parallel lines AB and De cut by the transversals AE and BD in the picture Which statement best explains the relationship between ABC and ED class=

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ANSWER:

2nd option: ΔABC ~ ΔEDC, because m<3 = m<4 and m<1 = m<5

STEP-BY-STEP EXPLANATION:

In order to answer the question we must take into account the difference between similarity and congruence.

We can see it in the following image:

That is, similar have the same figure but not the same size, while congruent have the same size and the same figure.

We can see that in this case the triangles are similar, we know this since angles 3 and 4 are equal because they share a vertex.

So the correct answer is the 2nd option: ΔABC ~ ΔEDC, because m<3 = m<4 and m<1 = m<5

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