Question

How much time is required for a car engine to do 278 kJ of work, if its maximum power is 95 kW?

Answer 1

W= work = 278 kj

P = Power = 95 Kw

t= time

P = W / t

Isolate t

t = W /P

Replacing:

t= 278kj / 95Kw = 2.93 seconds

It is required 2.93 seconds