Hello! I need some assistance with this homework question for precalculus, please?HW Q27
![Hello I need some assistance with this homework question for precalculus pleaseHW Q27 class=](https://us-static.z-dn.net/files/ddc/e76dd2af259e0c9e4edbde7ae92a0124.png)
The expression is given to be:
[tex]\log_55^{86}[/tex]Recall the rule of logarithms:
[tex]\log a^b=b\log a[/tex]Thus the expression becomes:
[tex]\log_55^{86}=86\log_55[/tex]Recall the rule:
[tex]\log_aa=1[/tex]Hence, we have the expression to be:
[tex]86\log_55=86[/tex]The answer is 86.