Question

thank you for viewing my question I seem to be stuck on this and need help thank you

Answer 1

ANSWER

$\begin{gathered} A=\frac{1}{4} \\ B=\frac{1}{2} \\ C=\frac{1}{4} \end{gathered}$

EXPLANATION

From the given data;

Event A; Alternating even and odd numbers means;

EOE and OEO

Number of favourable outcome is 2 while number of possible outcome is 8

Hence, the probability of Event A IS;

$\begin{gathered} Prob(A)=\frac{2}{8} \\ =\frac{1}{4} \end{gathered}$

In Event B; More even numbers than odd means having;

EEE,OEE,EEO and EOE

$\begin{gathered} EEE,OEE,EEOandEOE \\ Prob(B)=\frac{4}{8} \\ =\frac{1}{2} \end{gathered}$

For Event C; an even number on both the first and the last rolls;

EEE and EOE

$\begin{gathered} EEEandEOE \\ Prob(C)=\frac{2}{8} \\ =\frac{1}{4} \end{gathered}$