(b) Determine the kilocalories needed to heat 2.55 kg water from 21 °C to 37 °C.
![b Determine the kilocalories needed to heat 255 kg water from 21 C to 37 C class=](https://us-static.z-dn.net/files/d4c/e874650e28095c2bc4b2b3f8a9f9b33c.png)
Calculations:
We are given the following parameters :
• Mass = 2.55kg = 2.55*1000= 2550
,• T1 = 21°C
,• T2 = 37°C
,• Specific heat of water = c = 1cal/g°C
We will calculate q (heat ) as follows :
[tex]\begin{gathered} Q\text{ = m }\cdot c\cdot\Delta T \\ \text{ = 255}0\cdot\text{ }1\cdot\text{ ( 37-21)} \\ \text{ =}2550\cdot\text{ 16} \\ \text{ = 40800 calories }\ldots\ldots(\text{divide by 1000 to get to kilicalories) } \\ \text{ =40.8 kilocalories } \end{gathered}[/tex]